git-read-tree - Man Page

If only 1 tree is specified, git read-tree operates as if the user did not specify -m, except that if the original index has an entry for a given pathname, and the contents of the path match with the tree being read, the stat info from the index is used. (In other words, the index’s stat()s take precedence over the merged tree’s).

That means that if you do a git read-tree -m <newtree> followed by a git checkout-index -f -u -a, the git checkout-index only checks out the stuff that really changed.

This is used to avoid unnecessary false hits when git diff-files is run after git read-tree.

Typically, this is invoked as git read-tree -m $H $M, where $H is the head commit of the current repository, and $M is the head of a foreign tree, which is simply ahead of $H (i.e. we are in a fast-forward situation).

When two trees are specified, the user is telling git read-tree the following:

1. The current index and work tree is derived from $H, but the user may have local changes in them since $H.
2. The user wants to fast-forward to $M.

In this case, the git read-tree -m $H $M command makes sure that no local change is lost as the result of this "merge". Here are the "carry forward" rules, where "I" denotes the index, "clean" means that index and work tree coincide, and "exists"/"nothing" refer to the presence of a path in the specified commit:

        I                   H        M        Result
       -------------------------------------------------------
     0  nothing             nothing  nothing  (does not happen)
     1  nothing             nothing  exists   use M
     2  nothing             exists   nothing  remove path from index
     3  nothing             exists   exists,  use M if "initial checkout",
                                     H == M   keep index otherwise
                                     exists,  fail
                                     H != M

        clean I==H  I==M
       ------------------
     4  yes   N/A   N/A     nothing  nothing  keep index
     5  no    N/A   N/A     nothing  nothing  keep index

     6  yes   N/A   yes     nothing  exists   keep index
     7  no    N/A   yes     nothing  exists   keep index
     8  yes   N/A   no      nothing  exists   fail
     9  no    N/A   no      nothing  exists   fail

     10 yes   yes   N/A     exists   nothing  remove path from index
     11 no    yes   N/A     exists   nothing  fail
     12 yes   no    N/A     exists   nothing  fail
     13 no    no    N/A     exists   nothing  fail

        clean (H==M)
       ------
     14 yes                 exists   exists   keep index
     15 no                  exists   exists   keep index

        clean I==H  I==M (H!=M)
       ------------------
     16 yes   no    no      exists   exists   fail
     17 no    no    no      exists   exists   fail
     18 yes   no    yes     exists   exists   keep index
     19 no    no    yes     exists   exists   keep index
     20 yes   yes   no      exists   exists   use M
     21 no    yes   no      exists   exists   fail

In all "keep index" cases, the index entry stays as in the original index file. If the entry is not up to date, git read-tree keeps the copy in the work tree intact when operating under the -u flag.

When this form of git read-tree returns successfully, you can see which of the "local changes" that you made were carried forward by running git diff-index --cached $M. Note that this does not necessarily match what git diff-index --cached $H would have produced before such a two tree merge. This is because of cases 18 and 19 — if you already had the changes in $M (e.g. maybe you picked it up via e-mail in a patch form), git diff-index --cached $H would have told you about the change before this merge, but it would not show in git diff-index --cached $M output after the two-tree merge.

Case 3 is slightly tricky and needs explanation. The result from this rule logically should be to remove the path if the user staged the removal of the path and then switching to a new branch. That however will prevent the initial checkout from happening, so the rule is modified to use M (new tree) only when the content of the index is empty. Otherwise the removal of the path is kept as long as $H and $M are the same.

Each "index" entry has two bits worth of "stage" state. stage 0 is the normal one, and is the only one you’d see in any kind of normal use.

However, when you do git read-tree with three trees, the "stage" starts out at 1.

This means that you can do

$ git read-tree -m <tree1> <tree2> <tree3>

and you will end up with an index with all of the <tree1> entries in "stage1", all of the <tree2> entries in "stage2" and all of the <tree3> entries in "stage3". When performing a merge of another branch into the current branch, we use the common ancestor tree as <tree1>, the current branch head as <tree2>, and the other branch head as <tree3>.

Furthermore, git read-tree has special-case logic that says: if you see a file that matches in all respects in the following states, it "collapses" back to "stage0":

• stage 2 and 3 are the same; take one or the other (it makes no difference - the same work has been done on our branch in stage 2 and their branch in stage 3)
• stage 1 and stage 2 are the same and stage 3 is different; take stage 3 (our branch in stage 2 did not do anything since the ancestor in stage 1 while their branch in stage 3 worked on it)
• stage 1 and stage 3 are the same and stage 2 is different take stage 2 (we did something while they did nothing)

The git write-tree command refuses to write a nonsensical tree, and it will complain about unmerged entries if it sees a single entry that is not stage 0.

OK, this all sounds like a collection of totally nonsensical rules, but it’s actually exactly what you want in order to do a fast merge. The different stages represent the "result tree" (stage 0, aka "merged"), the original tree (stage 1, aka "orig"), and the two trees you are trying to merge (stage 2 and 3 respectively).

The order of stages 1, 2 and 3 (hence the order of three <tree-ish> command-line arguments) are significant when you start a 3-way merge with an index file that is already populated. Here is an outline of how the algorithm works:

• if a file exists in identical format in all three trees, it will automatically collapse to "merged" state by git read-tree.
• a file that has any difference what-so-ever in the three trees will stay as separate entries in the index. It’s up to "porcelain policy" to determine how to remove the non-0 stages, and insert a merged version.

• the index file saves and restores with all this information, so you can merge things incrementally, but as long as it has entries in stages 1/2/3 (i.e., "unmerged entries") you can’t write the result. So now the merge algorithm ends up being really simple:

  • you walk the index in order, and ignore all entries of stage 0, since they’ve already been done.
  • if you find a "stage1", but no matching "stage2" or "stage3", you know it’s been removed from both trees (it only existed in the original tree), and you remove that entry.
  • if you find a matching "stage2" and "stage3" tree, you remove one of them, and turn the other into a "stage0" entry. Remove any matching "stage1" entry if it exists too. .. all the normal trivial rules ..

You would normally use git merge-index with supplied git merge-one-file to do this last step. The script updates the files in the working tree as it merges each path and at the end of a successful merge.

When you start a 3-way merge with an index file that is already populated, it is assumed that it represents the state of the files in your work tree, and you can even have files with changes unrecorded in the index file. It is further assumed that this state is "derived" from the stage 2 tree. The 3-way merge refuses to run if it finds an entry in the original index file that does not match stage 2.

This is done to prevent you from losing your work-in-progress changes, and mixing your random changes in an unrelated merge commit. To illustrate, suppose you start from what has been committed last to your repository:

$ JC=`git rev-parse --verify "HEAD^0"`
$ git checkout-index -f -u -a $JC

You do random edits, without running git update-index. And then you notice that the tip of your "upstream" tree has advanced since you pulled from him:

$ git fetch git://.... linus
$ LT=`git rev-parse FETCH_HEAD`

Your work tree is still based on your HEAD ($JC), but you have some edits since. Three-way merge makes sure that you have not added or modified index entries since $JC, and if you haven’t, then does the right thing. So with the following sequence:

$ git read-tree -m -u `git merge-base $JC $LT` $JC $LT
$ git merge-index git-merge-one-file -a
$ echo "Merge with Linus" | \
  git commit-tree `git write-tree` -p $JC -p $LT

what you would commit is a pure merge between $JC and $LT without your work-in-progress changes, and your work tree would be updated to the result of the merge.

However, if you have local changes in the working tree that would be overwritten by this merge, git read-tree will refuse to run to prevent your changes from being lost.

In other words, there is no need to worry about what exists only in the working tree. When you have local changes in a part of the project that is not involved in the merge, your changes do not interfere with the merge, and are kept intact. When they do interfere, the merge does not even start (git read-tree complains loudly and fails without modifying anything). In such a case, you can simply continue doing what you were in the middle of doing, and when your working tree is ready (i.e. you have finished your work-in-progress), attempt the merge again.